19). A force of 60N keeps a mass of 0.20 kg in a circular pathat 120 rev/min. a)

Question

19). A force of 60N keeps a mass of 0.20 kg in a circular pathat 120 rev/min. a) Clearly calculate the angular velocity (in rad/sec) forthis mass.                          Note: 2 rad = 1 rev = 360o b) Clearly calculate the radius and linear velocity. 19). A force of 60N keeps a mass of 0.20 kg in a circular pathat 120 rev/min. a) Clearly calculate the angular velocity (in rad/sec) forthis mass.                          Note: 2 rad = 1 rev = 360o b) Clearly calculate the radius and linear velocity. b) Clearly calculate the radius and linear velocity.

Explanation / Answer

        Force, F = 60 N         Mass, M = 0.20 kg          (a)          Angular velocity, = 120 rev/min                                       = 120 * ( 2 / 60 ) rad/s                                       = 4 rad/s                                       = 12.56 rad/s ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~           (b)            Centripetal force, F = M 2 R             Radius, R = F / ( M 2 )                             = 60 / ( 0.2 * 12.56 2 )                             = 1.9 m            Linear velocity, V = R                                       = 1.9 * 12.56                                       = 23.9 m/s

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