y=Asin(kx-t+). For a transverse harmonic wave traveling in the negativex-directi

Question

y=Asin(kx-t+).

For a transverse harmonic wave traveling in the negativex-direction we have

y=Asin(kx+t+).

In this problem is zero. You have to watch forthe + or – sign.

From the notes:

Consider a transverse harmonic wave traveling in thepositivex-direction. The displacement y of a particle in themedium is given as a function of x and t by

y(x,t) = Asin(kx - t + ).

For a transverse harmonic wave traveling in the negative x-direction wehave

y(x,t) = Asin(kx + t + ).

Here k is the wavenumber, k = 2/,and = 2/T = 2f is the angularfrequency of the wave.   is called thephase constant.

The speed v of the wave can be expressed in terms of thesequantities.

v = f = /k.

Here y = (0.1m)sin(0.4x+5t).

The + sign indicates that the wave is traveling in the negativex direction and
k = 0.4, = 5, and = 0.

v = /k.

Explanation / Answer

v=w/k so v=12.5 as + sign indicates poistive directions so positive direction

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