A 32 kg skier skis directly down a frictionless slope angledat 12° to the horizo

Question

A 32 kg skier skis directly down a frictionless slope angledat 12° to the horizontal. Choose the positive direction of thex axis to be downhill along the slope. A wind force withcomponent Fx acts on the skier. What isFx if the magnitude of the skier's velocity is(a) constant, (b) increasing at a rate of 1.4 m/s2, and(c) increasing at a rate of 2.8 m/s2. Part C was the only part that I got right and I followedcramster.... A 32 kg skier skis directly down a frictionless slope angledat 12° to the horizontal. Choose the positive direction of thex axis to be downhill along the slope. A wind force withcomponent Fx acts on the skier. What isFx if the magnitude of the skier's velocity is(a) constant, (b) increasing at a rate of 1.4 m/s2, and(c) increasing at a rate of 2.8 m/s2. Part C was the only part that I got right and I followedcramster....

Explanation / Answer

force down the slope  + force up the slope =   m a . mg sin12    +Fx     =   m a . Fx   =    - mgsin12  + ma     for all threeparts . (a)   Fx = - 32 * 9.80 *sin12  + 32 * 0 =     - 65.20 Newtons . (b) Fx = -32 * 9.80 * sin12 + 32* 1.4   =     - 20.40newtons . (c)   Fx =   -32 * 9.80 *sin12   + 32 * 2.8   =     24.40 Newtons          watch the signs...

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