(a) What is the magnitude and direction of theimpulse imparted to the ball? magn
ID: 1728547 • Letter: #
Question
(a) What is the magnitude and direction of theimpulse imparted to the ball? magnitude 1 kg · m/s direction 2°counterclockwise from the +x-axis(b) If the ball (m = 0.147 kg)and bat are in contact for a time of 7.8ms, what is the magnitude of the average force of the bat on theball?
3 N
Compare this answer to the weight of the ball.
The contact force is 4 timesthe ball's weight.
(c) What is the impulse imparted to the bat?
magnitude 5 kg · m/s direction 6°counterclockwise from the +x-axis magnitude 1 kg · m/s direction 2°counterclockwise from the +x-axis
Explanation / Answer
. Initial velocity (vi ) = 39 i m /s . Final velocity (vf ) = 54 cos45 i + 54 sin45 j . = 38.18 i + 38.18 j . (a) Momentum is : P = m( vf - vi ) = 0.147 ( 38.18 i + 38.18 j - 39 i ) . = -0.120 i + 5.61 j . Magnitude is : sqrt [(-0.120)2 + (5.61)2 ] = 5.6 kg -m/s . Direction is : = tan-1 ( 5.61 / -0.120) = ----- degree . (b) Average force exerted is : . F = P / t = 5.6 / ( 7.8 * 10-3 ) = ---------- N . (c) Weight of the ball is : m g = 0.147 * 9.8 = 1.4406 . Hence contact force is 3.88 times the ball's weight. . (d) Impulse imparted on bat is equal inmagnitude but opposite in direction. . Tins is from Newton'sthird law. . Hope this helps u!Related Questions
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