Starting from rest, a basketball rolls from the top of a hillto the bottom, reac

Question

Starting from rest, a basketball rolls from the top of a hillto the bottom, reaching a translational speed of 3.54 m/s. Ignorefrictional losses. (a) What is the height of the hill? _____m (b) Released from rest at the same height, a can of frozenjuice rolls to the bottom of the same hill. What is thetranslational speed of the frozen juice can when it reaches thebottom? ____m/s. Starting from rest, a basketball rolls from the top of a hillto the bottom, reaching a translational speed of 3.54 m/s. Ignorefrictional losses. (a) What is the height of the hill? _____m (b) Released from rest at the same height, a can of frozenjuice rolls to the bottom of the same hill. What is thetranslational speed of the frozen juice can when it reaches thebottom? ____m/s.

Explanation / Answer

.    Here   mgh =0.5mv2   .
   or gh= 0.5 v2   .
   or    h = (0.5 *(3.54)2)/9.8 = 0.639 m
.
b) As the object is releasing from the sameheight .    m g h = 0.5 m v2   .
      v = sqrt(2 g h) = sqrt(2 * 9.8 *0.639) = 3.538 m/s . Hope this helps u!

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