A 7.0 g bullet is fired into a 1.5 kg ballistic pendulum. Thebullet emerges from

Question

A 7.0 g bullet is fired into a 1.5 kg ballistic pendulum. Thebullet emerges from the block with a speed of 200 m/s, and theblock rises to a maximum height of 10.7cm. Find the initial speed of the bullet.
1 m/s
N/B Please partial solution will not help me. A 7.0 g bullet is fired into a 1.5 kg ballistic pendulum. Thebullet emerges from the block with a speed of 200 m/s, and theblock rises to a maximum height of 10.7cm. Find the initial speed of the bullet.
1 m/s
N/B Please partial solution will not help me.

Explanation / Answer

    Mass ofd the bullet, m = 0.007 kg     Mass of the block, M = 1.5 kg     Velocity of the bullet before collision = U     Velocity of the bullet after collision, V = 200m/s     Velocity of the block after collision = V'     Maximum height raised by the block, h = 0.107m     Kinetic energy of the block at the lowest point= Potential energy the block at the highest point                                ( 1/2 ) M V ' 2 = M g h                                                 V ' = ( 2 g h )                                                      = ( 2 * 9.8 * 0.107 )                                                      = 1.45 m/s     From the law of conservation of momentum,     Momentum of the bullet before collision =Momentum of the bullet + lock after collision     m U = m V + M V'     0.007 U = 0.007 * 200 + 1.5 * 1.45     Velocity of the bullet before collision, U = (1.4 + 2.175 ) / 0.007                                                                 = 510.7 m/s

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