A 6kg object is lifted vertically through a distance of 5m by a light string und

Question

A 6kg object is lifted vertically through a distance of 5m by a light string under a tension of 80.0N. Find

a) The work done by the force of tension
b) The work done by gravity
c) The final speed of the object if it starts from rest

A train of mass 2.4X106 Kg enter a 5-km stretch of track with a vertical rise of 40m at a speed of 1.0m/s and leaves at 3.0m/s. Assuming that frictional drag is negligible find:

a)each term of the equation Win = ?K + ?U + Wout

b)Average mechanical power delivered by the engine for the climb if it is done at a constant acceleration

Explanation / Answer

Multiple question post but I'll do the first one
ET = Fy = 80(5) = 400 J
Eg = -Wy = -6 * 9.81 * 5 = -294.3 J

total Fy = ma
-W + T = ma
-9.81 * 6 + 80 = 6a
6a = 21.14
a = 3.523 m/s2

v2 = 2ay
v2 = 2 * 3.523 * 5
v2 = 35.23
v = 5.935 m/s 

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