A wagon is rolling forward on level ground. Friction isnegligible. The person si

Question

A wagon is rolling forward on level ground. Friction isnegligible. The person sitting in the wagon is holding a rock. Thetotal mass of the wagon, rider, and rock is 91 kg. The mass of therock is 0.25 kg. Initially the wagon is rolling forward at a speedof 0.53 m/s. Then the person throws the rock with a speed of 16m/s. Both speeds are relative to the ground. Find the speed of thewagon after the rock is thrown (a) directlyforward in one case and (b) directly backward inanother. i just need to see the steps! thanks! A wagon is rolling forward on level ground. Friction isnegligible. The person sitting in the wagon is holding a rock. Thetotal mass of the wagon, rider, and rock is 91 kg. The mass of therock is 0.25 kg. Initially the wagon is rolling forward at a speedof 0.53 m/s. Then the person throws the rock with a speed of 16m/s. Both speeds are relative to the ground. Find the speed of thewagon after the rock is thrown (a) directlyforward in one case and (b) directly backward inanother. i just need to see the steps! thanks!

Explanation / Answer

    Total Mass of wagon + rider + rock = 91 kg     Mass of the rock, m1 = 0.25 kg     Mass of wagon + rider, m2 = 91 - 0.25                                              = 90.75 kg     Initial speed of wagon + rider + rock beforethrowing rock, V1 = 0.53 m/s     Final speed of the rock after throwing rock =V2     Final speed of wagon + person after throwingrock, V = ? (a)     V2 = 16 m/s   ( Here ' + ' signrepresents that the rock is thrown in the same direction of motionof wagon )     Total initial momentum = Total finalmomentum     ( m1 + m2 ) V1 = m1 V2 + m2 V     91 * 0.53 = 0.25 * 16 + 90.75 * V     48.23 = 4 + 90.75 V     Final speed of wagon + person after throwingrock, V = 0.49 m/s (b)     V2 = - 16 m/s   ( Here ' - ' signrepresents that the rock is thrown in the opposite direction ofmotion of wagon )     Total initial momentum = Total finalmomentum     ( m1 + m2 ) V1 = m1 V2 + m2 V     91 * 0.53 = 0.25 * - 16 + 90.75 * V     48.23 = - 4 + 90.75 V     Final speed of wagon + person after throwingrock, V = 0.58 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.