A person stands in a stationary canoe and throws a 5.00 kg stone with a velocity
ID: 1726951 • Letter: A
Question
A person stands in a stationary canoe and throws a 5.00 kg stone with a velocity of 8.10 m/s at an angle of 28.0° above thehorizontal. The person and canoe have a combined mass of 105 kg.Ignoring air resistance and effects of the water, find thehorizontal recoil velocity (magnitude and direction) of the canoe. magnitude 1 m/s direction 2---Select---at right angles to the horizontal component ofthe velocity of the stoneopposite the horizontal component of the velocityof the stonealong the horizontal component of the velocity ofthe stone magnitude 1 m/s direction 2---Select---at right angles to the horizontal component ofthe velocity of the stoneopposite the horizontal component of the velocityof the stonealong the horizontal component of the velocity ofthe stoneExplanation / Answer
m1 u cos = (m1 +m2) v2 (5.00 kg) (8.10 m / s) (cos28.0o) =(105 kg) v2 v2 = .......... m / s
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