QuestionDetails: A 15.0-kg block rests on a horizontal table and is attached to

Question

QuestionDetails: A 15.0-kg block rests on a horizontal table and is attached to oneend of a massless, horizontal spring. By pulling horizontally onthe other end of the spring, someone causes the block to accelerateuniformly and reach a speed of 5.00 m/s in 0.500 s. In the process,the spring is stretched by 0.200 m. The block is then pulled at aconstant speed of 5.00 m/s, during which time the springis stretched by only 0.0500 m. Find (a) the springconstant of the spring and (b) the coefficient ofkinetic friction between the block and the table. QuestionDetails:

Explanation / Answer

Given : Mass of the block m = 15kg final velocity v = 5m/s time t = 0.5s spring constant = k the extension of the spring x1 = 0.2m a) In the first case,                        F1- Ffr = ma                          Or  F1= ma + Ffr                        Or kx1 = ma + s mg                         Or  k = m( a +s g ) / x1 The acceleration iscalculated using the equation of motion
                               a = v - u / t
substituting the values the spring constant ' k ' iscalculated. b) In the secondprocess we have                               F2 - Ffr = 0 as it is moving with constantspeed                                 Or kx2 = s mg                                   Or s = kx2 /mg Here x2 isthe stretch of the spring = 0.05m Solve it I hope it helps you Solve it I hope it helps you

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.