QuestionDetails: A .80-m aluminum bar is held with its length parallel to theeas
ID: 1674820 • Letter: Q
Question
QuestionDetails: A .80-m aluminum bar is held with its length parallel to theeast-west direction and dropped from a bridge. Just before the barhits the river below, its speed is 22 m/s, and the emf inducedacross its length is 6.5 X 10^-4 V. Assuming the horizontalcomponent of the earth's magnetic field at the location of the barpoints directly north, a) determine the magnitude of the horizontalcomponent of the earth's magnetic field, and b) state whether theeast end or the west end of the bar is positive. QuestionDetails: QuestionDetails: A .80-m aluminum bar is held with its length parallel to theeast-west direction and dropped from a bridge. Just before the barhits the river below, its speed is 22 m/s, and the emf inducedacross its length is 6.5 X 10^-4 V. Assuming the horizontalcomponent of the earth's magnetic field at the location of the barpoints directly north, a) determine the magnitude of the horizontalcomponent of the earth's magnetic field, and b) state whether theeast end or the west end of the bar is positive.Explanation / Answer
E = / t = B A / t = B L x/ t = B L v where L isthe length of the bar B = E / (L * v) = 6.5 * 10E-4 / (.8 * 22) = 3.69 *10E-5 horizontal component of field F = q v X B Using the right rule v X B pointsto the east - the direction a + charge would move So the East end of the bar is positive (the electrons in thebar will move to the West) Using the right rule v X B pointsto the east - the direction a + charge would move So the East end of the bar is positive (the electrons in thebar will move to the West)Related Questions
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