i need help please... i have tried everything. an athlete whirls a 7.0 kg hammer
ID: 1726048 • Letter: I
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i need help please... i have tried everything. an athlete whirls a 7.0 kg hammer tied to the end of a 1.3 mchain in a horizontal circle. The hammer makes on revolution in 1.0s. a) what is the centripetal acceleration of the hammer? answer:ac= 51.27 m/s ^2 b) what is the tension in the chain? answer: Fnet= 358.89N if you could show me how to do it, that would be great, anyhelp is greatly appreciated i need help please... i have tried everything. an athlete whirls a 7.0 kg hammer tied to the end of a 1.3 mchain in a horizontal circle. The hammer makes on revolution in 1.0s. a) what is the centripetal acceleration of the hammer? answer:ac= 51.27 m/s ^2 b) what is the tension in the chain? answer: Fnet= 358.89N if you could show me how to do it, that would be great, anyhelp is greatly appreciatedExplanation / Answer
Given: m = 7 r = 1.3 T = 1 (a) a = 4(pi^2)r/(T^2)=4*(pi^2)*1.3/(1^2)=51.32 (b) T = ma=7*51.32=359.24
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