from the equation V^2 = 2(-e) [ (1/4 pi Eo) ( -e / r + -e / r )] / m why is V sq
ID: 1725618 • Letter: F
Question
from the equation V^2 = 2(-e) [ (1/4 pi Eo) ( -e / r + -e / r )] / m why is V squared by 2?? i dont understand... what is the physics of the problem, that u have to make Vsquared? and i dont understand why theres a 2 behind (-e),, why do wetimes that equation by 2??? from the equation V^2 = 2(-e) [ (1/4 pi Eo) ( -e / r + -e / r )] / m why is V squared by 2?? i dont understand... what is the physics of the problem, that u have to make Vsquared? and i dont understand why theres a 2 behind (-e),, why do wetimes that equation by 2???Explanation / Answer
for simplicity we use the conservation of energytaking the potential energy to be zero when the moving electron isfar
away from the fixed electrons
the final potential energy will be
Uf = 2 e2 / 4 o d
where d is half the distance between the fixedelectrons
the initial kinetic energy is
Ki = (1 / 2) m v2
where m is the mass of the electron and v is theinitial speed of the electron
the final kinetic energy is zero
thus
Ki = Uf
= (1 / 2) mv2
= 2 e2 / 4 o d
solve for v
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