from County D, and 1006 adults from Country E were asked whether national identi
ID: 2949169 • Letter: F
Question
from County D, and 1006 adults from Country E were asked whether national identihy is strongly tied to birthplace Round to tree decimal places as needed.) The 00% corlden nerval forte poporton of adds tom Country B who say nahral anitysstrogy tedtobrtplece-C Round to three deoimal places as needed.) D (Round to tree decimal places as needed) The 90% confidenco irterval for to proporton of ad tstom Courtry D wno say rato " derity is worly ted to brtpace i. Round to three decimal places as needed) tor the proportion of sdtuts fom Country E who say national seny is ony te lce Round to Eree decimal places as needed.) MacBook Air 1 8 2Explanation / Answer
Solution :
Given that country A : n = 1013 , p = 0.35 , q = 1-p = 0.65
=> For 99% confidence interval, Z = 2.576
=> The 99% confidence interval of the proportion of adults from country A is
=> p +/- Z*sqrt(p*q/n)
=> 0.35 +/- 2.576*sqrt(0.35*0.65/1013)
=> (0.311,0.389)
Given that Country B : n = 995 , p = 0.19 , q = 1-p = 0.81
=> The 99% confidence interval of the proportion of adults from country B is
=> p +/- Z*sqrt(p*q/n)
=> 0.19 +/- 2.576*sqrt(0.19*0.81/995)
=> (0.158 , 0.222)
Given that Country C : n = 1002 , p = 0.24 , q = 1-p = 0.76
=> The 99% confidence interval of the proportion of adults from country C is
=> p +/- Z*sqrt(p*q/n)
=> 0.24 +/- 2.576*sqrt(0.24*0.76/1002)
=> (0.205 , 0.275)
Given that Country D : n = 1007 , p = 0.49 , q = 1-p = 0.51
=> The 99% confidence interval of the proportion of adults from country D is
=> p +/- Z*sqrt(p*q/n)
=> 0.49 +/- 2.576*sqrt(0.49*0.51/1007)
=> (0.449 , 0.531)
Given that Country E : n = 1006 , p = 0.10 , q = 1-p = 0.90
=> The 99% confidence interval of the proportion of adults from country E is
=> p +/- Z*sqrt(p*q/n)
=> 0.10 +/- 2.576*sqrt(0.10*0.90/1006)
=> (0.076 , 0.124)
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