An electric turntable 0.750 m in diameter is rotating about afixed axis with an

Question

An electric turntable 0.750 m in diameter is rotating about afixed axis with an initial angular speed of 0.250 rev/s and aconstant angular acceleration of 0.900 rev/s2. (a)Compute the angular velocity (in rad/s) of the turntable after0.200 s. (b) Through how many revolutions have the turntablespun during this time interval? (c) What is the tangentialspeed of a point on the rim of the turntable at t = 0.200s? (d) A 0.850-g bug is located on the rim of theturntable. What is the magnitude of the resultant force on thebug at t = 0.200 s?

Explanation / Answer

a) The angular velocity is               = o + t                  = (0.250 rev/s) + (0.90 rev/s2)(0.2s) b) The number of revolutions are                = (o) t + (1/2) t2 c) The tangential speed of a point on the rim turnableat t =2.00s is                v = r Here r = 0.375 m d)    The acceleration of the bug is                    a = r So the magnitude of the resultant force on the bug at t=0.200 s is             F = ma Here m = 0.850 kg Substitute the values.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.