An electric turntable 0.710 m in diameter is rotating about a fixed axis with an

Question

An electric turntable 0.710 m in diameter is rotating about a fixed axis with an initial angular velocity of 0.280 rev/s . The angular acceleration is 0.904 rev/s^2

(A)Compute the angular velocity after a time of 0.199 s

= ? rev/s

(B) Through how many revolutions has the blade turned in this time interval?

N = ? rev

(C) What is the tangential speed of a point on the tip of the blade at timet = 0.199 s ?

v = ? m/s

I am very behind and have no idea how to begin this. Thorough explanations greatly appreciated so I can learn. Thanks!!

Explanation / Answer

Converting to angular quantities:
1 = 0.28 rev/sec = 1.75929rad/s
= 0.904 rev/sec^2 =5.6799 rad/s^2

A. 2 = 1 + .t
2 = 1.759 + 5.6799 x 0.199 = 2.889 rad /s (0.4597 rev/s)

B. = 1.t + ½ .t^2
= (1.759 x 0.199) +( ½ x 5.679 x 0.199^2 )
= 0.462 rad ( 0.07352 revolutions)

C. v = R
v = 0.355 x 2.889 = 1.025m/s

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