Any help on this problem would be much appreciated! A 1.1-kg 14-cm-diameter soli
ID: 1725351 • Letter: A
Question
Any help on this problem would be much appreciated!A 1.1-kg 14-cm-diameter solid sphere is rotating about itsdiameter at 73 rev/min. (a) What is its kinetic energy (in joules)?
(b) If an additional 5.0 mJ of energy are supplied to therotational energy, what is the new angular speed of the ball (inrev/min)?
Thank you so much!
A 1.1-kg 14-cm-diameter solid sphere is rotating about itsdiameter at 73 rev/min. (a) What is its kinetic energy (in joules)?
(b) If an additional 5.0 mJ of energy are supplied to therotational energy, what is the new angular speed of the ball (inrev/min)?
Thank you so much! (a) What is its kinetic energy (in joules)?
(b) If an additional 5.0 mJ of energy are supplied to therotational energy, what is the new angular speed of the ball (inrev/min)?
Thank you so much!
Explanation / Answer
Mass, M = 1.1 kg Diameter, D = 0.14 m Radius, R = 0.07 m Angular velocity, = 73 rev / min = 73 * ( 2 / 60 ) rad / s = 7.64 rad / s Moment of Inertia of solid sphere about diameter , I = (2/5) M R 2 = 0.4 * 1.1 * 0.07 2 = 0.0020 kg m2 (a) Rotational Kinetic energy, KE rot = ( 1/2 ) I 2 = 0.5 * 0.0020 * 7.64 2 = 0.0584 J (b) Total energy , E = 0.0584 + 0.005 = 0.0634 J ( 1/2 ) I 2 = 0.0634 0.5 * 0.0020 2 = 0.0634 New angular velocity, = 7.96 rad / s = 7.96 * ( 60 / 2 ) rev / min = 76.1 rev / min
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