An lead block of volume 0.23 m 3 is suspended from a spring scaleand immersed in

Question

An lead block of volume 0.23 m3 is suspended from a spring scaleand immersed in a flask of water. Then the lead block is removed, and an aluminum block of thesame volume replaces it. (a) In which case is the buoyant force thegreatest, for the lead block or thealuminum block? 1 leadblock the buoyant force is the same foreach     aluminumblock

(b) In which case does the spring scale read the largest value? 2 aluminum block lead block    the scale reading is the same foreach

(c) Use the known densities of these materials to calculate thequantities requested in parts (a) and (b). Are your calculationsconsistent with your previous answers to part (a) and (b)?
Material Buoyant force Scale reading lead 3 N 4 N aluminum 5 N 6 N (a) In which case is the buoyant force thegreatest, for the lead block or thealuminum block? 1 leadblock the buoyant force is the same foreach     aluminumblock

(b) In which case does the spring scale read the largest value? 2 aluminum block lead block    the scale reading is the same foreach

(c) Use the known densities of these materials to calculate thequantities requested in parts (a) and (b). Are your calculationsconsistent with your previous answers to part (a) and (b)?
Material Buoyant force Scale reading lead 3 N 4 N aluminum 5 N 6 N 1 leadblock the buoyant force is the same foreach     aluminumblock 1 leadblock the buoyant force is the same foreach     aluminumblock 1 2 aluminum block lead block    the scale reading is the same foreach 2 aluminum block lead block    the scale reading is the same foreach 2 Material Buoyant force Scale reading lead 3 N 4 N aluminum 5 N 6 N

Explanation / Answer

The buoyant force is the same in both cases because thebuoyant force depends on the weight of the water displaced. FB = W V g    whereW is the density of water and FBthe buoyant force. The spring will read more for the lead block because the leadblock weighs more. Ss = V g (pb- W)    where Ss isthe spring scale reading for lead (Pb) SAL = V g (AL- W)    where Ss isthe spring scale reading for aluminum (AL) Substitute the needed values and solve Example: FB = 1000 kg/m3 * .23m3 * 9.8 m/s2 = 2254 N   thebuoyant force on either block SAL = V g (AL- W)    where Ss isthe spring scale reading for aluminum (AL) Substitute the needed values and solve Example: FB = 1000 kg/m3 * .23m3 * 9.8 m/s2 = 2254 N   thebuoyant force on either block

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.