A steel ball(66.45 g) shot in the horizontal direction, is caught by astationary

Question

A steel ball(66.45 g) shot in the horizontal direction, is caught by astationary pendulum (275.05 g). The pendulum rises 8.55 cm in thevertical direction. Calculate the momentum of the ball- pendulumsystem at the moment the ball is caught by the pendullum. I got this question wrong on my homework. I don't understandhow to do it. Please can someone help me. A steel ball(66.45 g) shot in the horizontal direction, is caught by astationary pendulum (275.05 g). The pendulum rises 8.55 cm in thevertical direction. Calculate the momentum of the ball- pendulumsystem at the moment the ball is caught by the pendullum. I got this question wrong on my homework. I don't understandhow to do it. Please can someone help me. I got this question wrong on my homework. I don't understandhow to do it. Please can someone help me.

Explanation / Answer

    Mass of the steel ball , m = 66.45 g     Mass of the stationary pendulum, M = 275.05g     Vertical rise, h = 8.55 cm     Velocity of steel ball + pendulum aftercollision = V     Kinetic energy of ball + pendulum at lowestpoint = Potential energy of ball + collision at highest point                 ( 1 / 2 ) ( m + M ) V 2 = ( m + M ) g h                                               V = ( 2 g h )                                                   = ( 2 * 980 * 8.55 )                                                   = 129.45 cm / s     momentum of ball + pendulum system = ( m + M )V                                                              = ( 66.45 + 275.05 ) 129.45                                                              = 44208.1 g cm/s                                                              = 0.44 kg m/s

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