An artillery shell accelerates in the barrelof a gun with an acceleration of 10,

Question

   An artillery shell accelerates in the barrelof a gun with an acceleration of 10,000 m/s2 for 0.04sand is fired at an angle 60o above the horizontal. Whatis the highest the shell will go after leaving the barrel? Plesae list out detailed steps and include a diagram. Thanks in advance.    An artillery shell accelerates in the barrelof a gun with an acceleration of 10,000 m/s2 for 0.04sand is fired at an angle 60o above the horizontal. Whatis the highest the shell will go after leaving the barrel? Plesae list out detailed steps and include a diagram. Thanks in advance.

Explanation / Answer

Accleration a = 10000 m / s ^2 time t= 0.04 s angle = 60 degrees Speed of the artillery v = at = 4 * 10 ^ 2 m /s required height H = ( v sin ) ^ 2 / 2g                            = 6122.44 m

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