7. A person stands on a scale in an elevator. As the elevatorstarts, the scale h

Question

7. A person stands on a scale in an elevator. As the elevatorstarts, the scale has a constant reading of 589 N. Later, as the elevator later stops, thescale reading is 395 N. Assume themagnitude of the acceleration is the same during starting andstopping.

(a) Determine the weight of the person.
1 N

(b) Determine the person's mass.
2 kg

(c) Determine the acceleration of the elevator.
3 m/s2 (a) Determine the weight of the person.
1 N

(b) Determine the person's mass.
2 kg

(c) Determine the acceleration of the elevator.
3 m/s2

Explanation / Answer

Given that the reading when it is stops is W1 = 395N The reading of scale is W2 = 589 N ------------------------------------------------------------- (a) If the elevator is at rest reading of scale is equal to weightof person                        mg = W1 = 395N (b) then the mass of person is m = W1 /g                                             m = 395 N / 9.8m/s2                                               = 40.30 kg (c) If the elevator moving with acceleration a       W2 - W1 = ma             a = ( W2 - W1 ) / m                             = 4.81 m/s2

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