A 70 kg trampoline artist jumpsvertically upward from the top of a platform with

Question

A 70 kg trampoline artist jumpsvertically upward from the top of a platform with a speed of5.5 m/s. (a) How fast is he going as he lands on the trampoline, 3.0 mbelow?
(b) If the trampoline behaves like a spring of spring constant5.2 * 104 N/m, how far does he depress it? hint: just the magnitude. Vertical spring. Take theorigin at undeflected position of spring. Consider both gravity andspring PE in depression. A 70 kg trampoline artist jumpsvertically upward from the top of a platform with a speed of5.5 m/s. (a) How fast is he going as he lands on the trampoline, 3.0 mbelow?
(b) If the trampoline behaves like a spring of spring constant5.2 * 104 N/m, how far does he depress it? hint: just the magnitude. Vertical spring. Take theorigin at undeflected position of spring. Consider both gravity andspring PE in depression.

Explanation / Answer

A 70 kg trampoline artist jumpsvertically upward from the top of a platform with a speed of5.5 m/s. (a) How fast is he going as he lands on the trampoline, 3.0 mbelow?

when he reaches the same point he attains the same speed.
now speed when he reaches 3m=5.5*5.5+2*9.8*3=9.43m/sec
(b) If the trampoline behaves like a spring of spring constant5.2 * 104 N/m, how far does he depress it?

1/2kx*x=kinetic energy
1/2*5.2*104*x*x=1/2*70*9.43*9.43
so x=0.3459m

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