A rescue helicopter lifts a 79kg person straight up by meansof a cable. The pers
ID: 1721639 • Letter: A
Question
A rescue helicopter lifts a 79kg person straight up by meansof a cable. The person has an upward acceleration of0.70m/s2 and is lifted from rest through a distance of11m. (a) What is the tension in the cable? How much work is done by(b) the tension in the cable and (c) the person's weight? (d) Usethe work-energy theorem and find the final speed of theperson. Cramster has parts (a), (b), and (c) answer ok but not(d). Missing part (D) Use the work-energy theorem and find the final speed of theperson. A rescue helicopter lifts a 79kg person straight up by meansof a cable. The person has an upward acceleration of0.70m/s2 and is lifted from rest through a distance of11m. (a) What is the tension in the cable? How much work is done by(b) the tension in the cable and (c) the person's weight? (d) Usethe work-energy theorem and find the final speed of theperson. Cramster has parts (a), (b), and (c) answer ok but not(d). Missing part (D) Use the work-energy theorem and find the final speed of theperson.Explanation / Answer
this problem you need to use the work energy theorem in d since the person has an upward acceleration of .7 m/s^2 you canfind how fast he is moving after 11m. once you find that speed, usethe acceleration of gravity (9.81 m/s^2) to figure out how muchfurther he travels upwards, i.e. he is going to stop going upwardswhen the acceleration of gravity cancels out his speed after thehelicopter has accelerated him for 11m. add these two distances together. Since he is now at rest and abovethe ground, we can use gravitational potential energy. PE = h*g*m where h is the two heightsadded together, g is gravity, and m is his weight. set PE = KE because the energy will be conserved when he reachesthe bottom. so PE = .5 * m * v^2 Solve for v
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