A shaft is driven by a 100 hp motor at 900 KPM A 16-inch diameter gear, estimate

Question

A shaft is driven by a 100 hp motor at 900 KPM A 16-inch diameter gear, estimated to weigh 1000 lbs. drives a mating gear on a second shaft. Find the forces transmitted between the pinion gear to the second gear it the pinion gear is a spur gear with a pressure angle of 25 degree the pinion gear is a helical gear with a pressure angle of 25 degree and a helix angle of 20 degree (on parallel shafts) the pinion gear is a bevel gear with a normal pressure angle of 25 degree, a spiral angle of 0". and a pitch cone angle of 25 degree for shafts at 90 degree, and the driving pinion has a right-hand spiral that rotates clockwise when viewed from its large end.

Explanation / Answer

(a) Tangential Force Ft = M / r     

                                     = power/ (angular velocity*r)         power = 55000 lbf ft/s , r = 8/12 ft

                                     = (55000 ) / (30pi*8/12)   = 875.3522 lbf tangential

       Radial Force Fr = Ft * tan(25) + 1000 = 1408.18 lbf

       Net force = sqrt(fr^2 + Ft^2 ) = 1658 lbf

b) Tangential Force Ft = M / r     

                                     = power/ (angular velocity*r)         power = 55000 lbf ft/s , r = 8/12 ft

                                     = (55000 ) / (30pi*8/12)   = 875.3522 lbf tangential

     Radial Force Fr = Ft * tan(25) / cos(20) = 434.38 lbf

     axial Force Fa = Ft * tan(20) = 318.6 lbf

      Net force = sqrt(Fr^2 + Ft^2 + Fa^2) = 1027.83 lbf

     

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