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A piston-device contains steam at 500 kPa and 50 percent quality. The initial vo

ID: 1717176 • Letter: A

Question

A piston-device contains steam at 500 kPa and 50 percent quality. The initial volume is 0.04 m^3. Determine the amount of heat addition required to increase the volume to 0.1554 m^3 at constant pressure. 0.75 kg of Refrigerant 134a a ta pressure of 400 kPa and quality of 60 percent is heated in a piston-cylinder device at constant pressure until the volume is doubled. The refrigerant is then compressed isothermally until the vapor has turned to saturated vapor. Show the activities on a T-v diagram, and determine: the temperature of the refrigerant at the end of the expansion process (degree C), the final pressure of the refrigerant (kPa), and the total heat involved (kJ).

Explanation / Answer

a) Given : Pressure of steam inlet P1 = 500 kPa = 500 x 10 ^3 Pa

1 Pa = 1N/m^2

1 bar = 1 x 10^5 N/m^2

= 0.5 bar

Dryness fraction x = 0.5

Volume V1 = 0.04 m^3

Volume V2 = 0.1554 m^3

Heat Addition = change in enthalpy

= h1 = h2

h1 at saturated steam and h2 at supersaturated steam

From steam tables at prerssure 500 KPa the specific enthlapy od steam hs = 2747.64 Kj/kg

dry ness fraction (x) = 0.5

latent heaat L = 2225.31 Kj/kg

Enthalpy h1 = h + XxL

2747.64 + 0.5 x 2225.31

= 3860.3 kj /kg

Enthalpy at 2

h2 = 2780 kj/kg at 500 kpa and temperature 151 C

Heat addition = h1 - h2

3860 - 2780

= 1080 kj / kg

b) Given ; Mass = m = 0.75 kg

Refregerant = R134a

Pressure P1 = 400 kpa = 0.4 MPa

Dryness fraction x = 0.6

find : Temperature of the refregerant at end of expansion = ?

Final pressure of the refregerant

total heat involved

enthalpy h1 = hf1 + Xx hfg1

from Refregerant tables of R134a

hf1 = 63 kj/kg, hfg1 = 252 kj/kg at pressure 0.4 MPa

h1 = 63 + 0.6 x 252

= 214.2 kj /kg

h1 = m x Cp (T2 - T1 )

214.2= 0.75 x 1.34 (10 - T2 )

T2 = 203 C

Total heat involved = h1 - h2

h2 = 252kj/ kg

h = 252.- 214.2

= 37 .8 kj /kg

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