Multisim Parallel Inductive Reactive Circuit Construct the series and parallel i

Question

Multisim Parallel Inductive Reactive Circuit

Construct the series and parallel inductive reactive circuits from this week’s assignment in MultiSIM and perform Single AC Frequency Analysis on each circuit to confirm your calculations. Use a 5% tolerance for each resistor or inductor.Capture a screenshot of the output of the analysis to confirm your calculations. Also, construct a table to show expected and measured results. With calculation and analysis please.

Include a discussion of any differences noticed between the calculations and the simulations.

Explanation / Answer

1) X150=j2*3.14*1000*150*10^-3=j942.47 ohms

X80=j2*3.14*1000*80*10^-3=j502.65 ohms

total impedance Z=(150+300+j(942047+502.62))=(450+j1445.12) ohms

total current i=15/(450+j1445.12)=9.9*10^-3<-72.7 amps

voltage across 150 ohms=150*9.9*10^-3<-72.7=1.485<-72.7 volts

voltage across 300 ohms=300*9.9*10^-3=2.97<-72.7 volts

voltage across 150 mH =j942.47*9.9*10^-3<-72.7=9.33<17.3 volts

voltage accross 80 mH=j502.64*9.9*10^-3<-72.7=4.976<17.3 volts

2) G1=1/150=6.667*10^-3 mhos

G2=1/300=3.33*10^-3 mhos

B1=1/(j502.65)=1.989*10^-3<-90 mhos

B2=1/(j942.47)=1.06*10^-3<-90 mhos

Y=G1+G2-(B1+B2)=9.997*10^-3-(3.049*10^-3<-90)=0.01045<16.96 MHOS

impedance Z=1/Y=/(0.010445<16.96)=95.6<-16.96 OHMS

total current i=15/(95.6<-16.96)=0.156<16.96 amps

current thrrough 150 ohms= 15/150=0.1 amps

current through 300 ohms=15/300=0.05 ampss

current through j502.65=15/(j502.65)=0.029814<-90 amps

current through j942.47=15/(j942.47)=0.0159<-90 amps

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