1. A fiber, used at 1550nm, has a core diameter of 0.004mm, n1 = 1.46, n2 = 1.45

Question

1. A fiber, used at 1550nm, has a core diameter of 0.004mm, n1 = 1.46, n2 = 1.455

i. Show that this is a single mode fiber.

ii. Compute and plot the MFD using the Petermann II and the Marcuse equations. Note where the fiber core is relative to the Gaussian approximation to the field.

iii. What is |E|^2 at r = a?

iv. Determine the V-number if the fiber is used at a wavelength of 1320nm.

v. Plot the same parameters the MFD using the Petermann II and the Marcuse equations. Note where the fiber core is relative to the Gaussian approximation to the field.

vi. What is |E|^2 at r = a?

Explanation / Answer

E= hc/wavelength

= 13.6(1/n12   - 1/n22 )

E= kq/r2

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