The steel framing plan of a small building is shown in the figure. The floor con

Question

The steel framing plan of a small building is shown in the figure. The floor consists of a 6-in- thick reinforced concrete slab supported on steel beams (see section 2-2). Beams are connected to each other and to the corner columns by clip angles (see section 1- 1). The clip angles are assumed to provide the equivalent of a pin support for the beams. An acoustical board ceiling which weighs 1.5 lb/ft2, is suspended from the concrete slab by closely spaced supports, and it can be treated as an additional uniform load on the slab. To account for the weight of ducts, piping, and conduit, located between the slab and ceiling (and supported by hangers from the slab), an additional dead load allowance of 20 lb/ft? is assumed. The designer initially estimates the weight of beams B1 at 30 lb/ft and the girders B2 on column lines 1 and 2 at 50 lb/ft. Establish the magnitude of the dead load distribution on beam B1 and girder B2 B3 91 -O Tribytary Area for B1 3 @ 10,-w

Explanation / Answer

Beam B1

Tributary width of B1=10ft

Thickness of slab=150*(6/12)=75psf

Total area load due to dead load =(75+1.5+20)=96.5 psf

Line load on beam B1=96.5*10=965 plf

Self weight of beam = 30plf

Total dirtributed load on B1=WD=965+30=995plf

Span of beam=28'

Rb = (995*28)/2000=13.93kips

Girder B2

On girder B2, there is uniform load due to self weight=50plf

WD=50 plf

P (@8' and 16' from support) = 13.93 kips

RD=(50*30/2000)+(2*13.93/2)=14.68 kips

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