1. Given: You are to construct a 1,100 foot long section of a levee that has a t
ID: 1711811 • Letter: 1
Question
1. Given: You are to construct a 1,100 foot long section of a levee that has a top width of 12 feet, side slopes of 3:1, and the following heights above existing grade: Station 0+00 5+50 11+00 Height 7.75 6.96 4.85 You are instructed to compact it to a dry unit weight of 114 pcf at an optimum moisture of 14%. The borrow material has an in-situ (most)unit weight of 100.8 pcf, a moisture content of 5%, and a particle density of 2.66 g/cm3. Its swell factor is 0.85 Find: a. The shrink factor for the soil. b. The required borrow volume, assuming 5% waste. c. How many gallons of water need to be added per loose cubic yard of soil? d. How many 8,000 gallon water truck loads would be needed to apply the water during placement? How many 25 cy loads would be needed to transport the soil, including waste? If the compacted material saturates due to rising water, what would its moisture content be? Express moisture content gravimetrically and volumetrically. e. f.Explanation / Answer
A)
Shrinkage Factor = (weight/bank unit volume)/(weight/compacted unit volume)
borrow density = 100.8 psf
compacted density ( bulk) = (1+w)*ydry = (1+0.14)*114 =129.96 psf
Shrinkage Factor = 110.8/129.96 = 0.7756
b)
between 00+00 to 05+50 average height = (7.75+6.96)/2=7.355 f
base width = 12+2*3*7.355=56.13 ft
between 05+50 to 11+00 average height = (4.85+6.96)/2=5.905 f
base width = 12+2*3*5.905=47.43 ft
total compacted volume = 550*(12+56.12)*7.355 +550*(12+47.43)*5.905/2= 234288.1063 ft3
volume of borrow = compacted volume / shrinkage factor = 234288.1063 /0.7756 =358716.7953 ft3
including 5% wastage
volume of borrow = 1.05*358716.7953 = 376652.63 ft3
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