Determine the Overturning Moment that must be resisted by the foundation, for th

Question

Determine the Overturning Moment that must be resisted by the foundation, for the following design criteria; Location: for Lat., Long., indicate the city and state Soil: V^bar_s = shear wave velocity N = blows per ft. s^bar_u = undrained shear strength Structure's Occupancy or Risk: Seismic Force Resisting System: -SEBF = Steel eccentrically braced frame -SSCBF = Steel special concentrically braced frame - SOCBF = Steel ordinary concentrically braced frame -SSMF = Steel special moment frame - SIMF = Steel intermediate moment frame - SOMF = Steel ordinary moment frame Floor/Roof weights: Floor/Roof locations: exponent k = 1.0 S_a = 1.006g S_MS = 1.104g S_DS = 0.736g S_1 = 0.386g S_M1 = 0.628g S_D1 = 0.419g The design criteria parameters are in the attached spreadsheet Determine the parameters that are blank in the spreadsheet. Use the USGS web site, and hand in the print-out form the USGS seismicity calculator. Submit pencil/paper calculations for C_S, V, F_1, F_2, M_1, M_2, M_Foundation.

Explanation / Answer

Given data,

W1=700 Kips=3115 KN

W2 = 550 Kips = 2448 KN

K= 1.0

STEP 1: footing size

P = Dead load + Live load

Now strength Demand (Pu) =1.2 DL + 1.6 L.L

STEP 2: design Capacity of foundation

The bearing capacity = 2000B = 2000* 15=30000psf = 30 Ksf

Now, Design capacity = Resistance factor * Bearing capacity * (width of foundation)2

0.7* 30*(15)2 =4725 Kips

STEP 3: design for shear

Calculate the value of Vu

But Vc > vu

STEP 4: calculate moment at the face of the wall

Mxx = Direct moment + moment due to eccentricity of applied axial load

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