It\'s a snowy day and you\'re pulling a friend along a level road on a sled. You

Question

It's a snowy day and you're pulling a friend along a level road on a sled. You've both been taking physics, so she asks what you think the coefficient of friction between the sled and the snow is. You've been walking at a steady 1.5;{ m m}/{ m s}, and the rope pulls up on the sled at a 37.0^circ angle. You estimate that the mass of the sled, with your friend on it, is 66.0 kg and that you're pulling with a force of 74.0 N.What answer will you give?

Explanation / Answer

Fy = -Mg + Tsin(a) = 0 => T = Mg/sin(37) Fx = Tcos(a) - uMgsin(s) = 0 => Mgcot(37)/(Mgsin37) = u => u = cos(37)/sin^2(37) = 1.84

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