A parallel plate capacitor is charged to a potential difference of 100 V and dis

Question

A parallel plate capacitor is charged to a potential difference of 100 V and disconnected from the source. A slab of dielectric is then inserted between the plates. Which of the following changes?
a. the potential difference
b. the capacitance
c. the charge on the plates
d. 1 and 2
e. all of the above
f. none of the above

2. Consider inserting a slab of dielectric material is inserted between the plates of a charged capacitor. The electric field in the dielectric is
a. largest near the positively charged plate.
b. the same everywhere.
c. largest near the negatively charged plate.
d. None of the above.


3.A certain amount of work is required to bring two point charges q near each other until they are a distance d apart. If the magnitude of the point charges were doubled to 2q, would the work required also double?
a. yes
b. no
C. It depends on the signs of the charges.
D. None of the above.

Explanation / Answer

1) The answer is ' d '. Because if we disconnected from the batery and
dielectric is placed between the plates then capacitance and potential difference are changed 2) The answer is ' b '. means the electric field is same everywhere 3) answer is ' a '. When the charge is double the doing work also double.

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