A parallel plate capacitor containing a dielectric material is charged by a batt

Question

A parallel plate capacitor containing a dielectric material is charged by a battery. Determine what change if any would occur when the battery and the dielectric material are removed. Assume that the plate separation remains fixed and that removing the battery causes the charge on the plates of the capacitor to remain constant. Circle the correct answer. Capacitance of the capacitor. Increases Decreases Constant Potential difference across the plates of the capacitor. Increases Decreases Constant Electric field between the plates. Increases Decreases Constant A parallel plate capacitor containing NO dielectric material is charged by a battery. Determine what change if any would occur if the battery remains connected (So that Voltage stays constant) and a dielectric material is inserted between the plates. Circle the correct answer. Capacitance of the capacitor. Increases Decreases Constant Potential difference across the plates of the capacitor. Increases Decreases Constant El

Explanation / Answer

8) The capacitance of a set of charged parallel plates is increased by the insertion of a dielectric material. The capacitance is inversely proportional to the electric field between the plates, and the presence of the dielectric reduces the effective electric field. So,

a) After removing dielectric, Capacitance decreases by dielectric constant [C = eoA/d]

b) Potential difference increases by dielectric constant.

c) Electric field increses by dielectric constant [E = V/d]

9) a) After insertion dielectric, Capacitance increases by dielectric constant [C = eoA/d]

b) Potential difference decreases by dielectric constant.

c) Electric field decreses by dielectric constant [E = V/d]

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