The Problem Reads: A system consists of a vertical spring with force constant k=
ID: 1708210 • Letter: T
Question
The Problem Reads:A system consists of a vertical spring with force constant k=1,250N/m, length L=1.50m, and object of mass m=5.00kg attached to the end. The objects is placed at the level of the point of attachment with the spring un-stretched, at position yi=L, and then it is released so that it swings like a pendulum. (a) Write Newton's second law symbolically for the system as the object passes through it's lowest point. (Note that at the lowest point, r=L-yf) (b) Write the conservation of energy equation symbolically, equating the total mechanical energies at the initial point and lowest point. (c) Find the coordinate position of the lowest point. (d) Will this pendulum's period be greater or less than the period of a simple pendulum with the same mass m and length mass L? Explain.
Explanation / Answer
A system consists of a vertical spring with force constant k=1,250N/m, length L=1.50m, and object of mass m=5.00kg attached to the end. The objects is placed at the level of the point of attachment with the spring un-stretched, at position yi=L, and then it is released so that it swings like a pendulum. (a) Write Newton's second law symbolically for the system as the object passes through it's lowest point. (Note that at the lowest point, r=L-yf) r = 1.50-yf and you know that y = L/i so r = 1.50 - (Lf/i) which means that r = 1.50 - 1.5f/i (b) Write the conservation of energy equation symbolically, equating the total mechanical energies at the initial point and lowest point. (c) Find the coordinate position of the lowest point. Again, we know that r = 1.5 - 1.5f/i We know yi = L, and that y = L/i r = 1.5 - 1.5(L/i)/i = 1.5 - 1.5L L = 1.5, right? So, r = 1.5 - (1.5 x 1.5) = -0.75 So, it's (1.5,-0.75) (d) Will this pendulum's period be greater or less than the period of a simple pendulum with the same mass m and length mass L? Explain.
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