A luge and its rider, with a total mass of 86 kg, emerge from a downhill track o

Question

A luge and its rider, with a total mass of 86 kg, emerge from a downhill track onto a horizontal straight track with an initial speed of 40 m/s. Assume that they stop with a constant deceleration of 2.3 m/s2.
(a) What magnitude F is required for the decelerating force?


(b) What distance d do they travel while decelerating?


(c) What work W is done on them by the decelerating force?


(d) What is F for a deceleration of 4.6 m/s2?


(e) What is d for a deceleration of 4.6 m/s2?


(f) What is W for a deceleration of 4.6 m/s2?

I have the answers that are looking for distance correct, but I can't seem to get W or F

Explanation / Answer

a) F=m*a F= 76 * -2.3 = -174.8 b) using energy .5*76*40^2=350*d solve for d=173.7 m c) 174.8*173.7=30365 J d) the deceleration is double so force also doubles F=349.6 e) This time distance will be half of the previous time. =86.85 m f) Work done will be same as it has same kinetic energy. 30365 J

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