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1.) When a charged particle moves at an angle of 15° with respect to a magnetic

ID: 1707833 • Letter: 1

Question

1.) When a charged particle moves at an angle of 15° with respect to a magnetic field, it experiences a magnetic force of magnitude F. At what angle (less than 90°) with respect to this field will this particle, moving at the same speed, experience a magnetic force of magnitude 1.8F?
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2.) A 45-m length of wire is stretched horizontally between two vertical posts. The wire carries a current of 74 A and experiences a magnetic force of 0.15 N. Find the magnitude of the earth's magnetic field at the location of the wire, assuming the field makes an angle of 50.0° with respect to the wire.
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Explanation / Answer

Magnetic force F = qvBsin force is directly proportional to the sin at constant velocity , B and q F_1 / F_2 = sin_1 / sin _2 given F_1 = F and F_2 = 1.8F _1 = 15^0 we have to find _2 solving for _2 = sin^-1(sin_1 * (F_2 / F_1)) plug the values _2 = 27.76^0 ------------------------------------- (2)magnetic force due to stright current carrying wire F = Bl*Isin B = F/ (l*I*sin ) Here l = length of the wire = 45 m I = current = 74 A Force = 0.15 N = 50^0 plug all the values B = 5.88*10^-5 T