1. Calculate the magnitude of the electric field at one corner of a square 0.95

Question

1. Calculate the magnitude of the electric field at one corner of a square 0.95 m on a side if the other three corners are occupied by 2.75x10-6 C charges.

answer in N/C

2. The electrostatic force between two charges located 4 meters apart is 0.16 N. What will the force be between these charges when they are located 1.6 meter
apart?

answer in Newtons

3. When two identical ions are separated by a distance of 3.4x10-10 m, the electrostatic force each exerts on the other is 8.0x10-9 N. How many electrons are missing from each ion?

answer is _______ electron(s)

Explanation / Answer

1. a = 0.95 m, q = 2.75x10-6 C

E = 2 * kq/a2 + kq/(2a)2 = kq(2 + 1/2)/a2 = 5.25*104 N/C

2. d = 4 m, F = 0.16 N. d' = 1.6 m, find F'

F = kqq'/d2, F' = kqq'/d'2

so F' = F*(d/d')2 = 1.0 N

3. d = 3.4x10-10 m, F = 8.0x10-9 N. find number of electrons N

F = kq2/d2, so q = d(F/q) =

N = q/e = d/e * (F/k) = 2

answer is 2 electrons

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