while skydiving, a physics student launches himself horizontally out of an airpl
ID: 1703484 • Letter: W
Question
while skydiving, a physics student launches himself horizontally out of an airplane that is flying at 12,500 feet above the Earth at a speed of 80 mph. the total mass of the student and his gear is 110 kg. assume g=9.8m/s2. answer the following:1) what is the magnitude of the gravitational force pulling on the student? A: 9.8m/s2 B: 980N C:1080N D:cant determined
2) if the wind resistance acting on the student is equal to 1/4 of his weight, what will his rate of acceleration be? A: 9.8m/s2 B: C: 0.75g, downward D: 0.25m/s2, upward
3) after opening the chute, the student begin to fall with constant vertical speed, what is the force of air resistance acting on the student and his parachute? A: 0 N B: 980N C: 1080N D: 2160N
4) if there were no air and thus no wind resistance (vacuum) what will be the end result of student jump? A: the chute will still open, but he will hit the ground slightly faster B: there is no gravity in a vacuum, so he would not fall C:The chute would still open but he would float more slowly toward the ground
Explanation / Answer
1) magnitude of gravitational force would be F=mg F=(9.8)*(110)= 1080 N Answer=C, 1080 N 2) Sum of Forces= ma Air Resistance - mg =ma (1080/4)-1080=(110)*a a=-7.35 Answer= C, .75g (.75*9.8)=7.35 since its downwards, this is negative 3) constant velocity means no acceleration Air Resistance - mg=0 Air Resistance= mg Air Resistance = 1080 N Answer= C, 1080 N 4)In a vacuum there is no air, thus no air resistance. When a parachute opens, it slows down the person because of air resistance. So in a vacuum, the parachute would still open but the person would fall faster because there is no air to slow them down. Answer= A
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