A farm truck moves due east with a constant velocity of 9.50 m/s on a limitless,

Question

A farm truck moves due east with a constant velocity of 9.50 m/s on a limitless, horizontal stretch on the back of the truck throws a can of soda upward and catches the projectile at the same location on the truck bed, but 16.0 m fatther down the road.
(a) in the frame of reference of the truck, at what angle to the vertical does the boy throw the can?

(b) what is the initial speed of the can relative to the truck?
(c) what is the shape of the can's trajectory as seen by the boy? aj observer's frame of reference,

(d) describe the shape of the can's path and

(e) determine the initial velocity of the can.

Explanation / Answer

the time of flight of the can by considering its horizontal motion

x = x_o+ v_ot + (1/2)at^2

16m = (9.50 m/s) t + 0

t = 1.68 s

a ) For the boy to catch the can at the same location on the truck bed, he must throw it
straight up, at 0° to the vertical.

b) For the free fall of the can,

y_f = y_i + v_y t + (1/2)ayt_2

0 = 0 + vyi (1.68 s) - (1/2)(9.8 m/s2)(1.68 s)^2

v_yi= 8.23 m/s

c ) The boy sees the can always over his head, traversing a straight line segment upward and then downward


d ) The ground observer sees the can move as a projectile on a symmetric section of a parabola opening downward.

Its initial velocity is

v_ o = v(9.5^2+ 8.23^2) = 12.5 m/s north

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