PART A:Through what potential difference must electrons be accelerated (from res

Question

PART A:Through what potential difference must electrons be accelerated (from rest) so that they will have the same wavelength as an x-ray of wavelength 0.190 nm ?

(Use 6.63×10-34 J*s for Planck's constant, 9.11×10-31kg for the mass of an electron, and 1.60×10-19C for the charge on an electron.)

PART B: Through what potential difference must electrons be accelerated so they will have the same energy as the x-ray in Part A?

(Use 6.63×10-34Js for Planck's constant, 3.00×10^8m/s for the speed of light in a vacuum, and 1.60×10-19C for the charge on an electron.)

Explanation / Answer

P=h/lamda=3.49e-24(kgm/s). so v=0.038e8=3.8e6(m/s). so U=mv^2/2e=41.7(V). -------------- Q=hc/lamda=1.046e-15(J). so Q=U*e so U=6540(V)

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