an actor with mass of 80kg has cloned himself. The clone has different mass, m.

Question

an actor with mass of 80kg has cloned himself. The clone has different mass, m. The clone stands on the brink of a cliff 36.0m high. The actor stands on top of a Humvee, 1.80m above the ground. Actor starts from rest and swings down on the ropse without friction. Then, actor undergoes an elastic head-on collision with the clone, seding him over the cliff.

is mechanical energy and/or momentum conserved throughout the action sequence? Is this principle sufficient to solve the problem? explain either or both.

Thanks Y'all^^

Explanation / Answer

when the actor his the clone, its speed is. Mg*(36-1.8)=Mv^2/2. so v=sqrt(2*34.2*g)=25.9(m/s). ------------- elastic collision. so velocity of the clone. v_1=(0*(m-80)+2*25.9*80)/(80+m)=4144/(80+m).

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