A 5000 {kg} African elephant has a resting metabolic rate of 2500 W. On a hot da

Question

A 5000 {kg} African elephant has a resting metabolic rate of 2500 W. On a hot day, the elephant's environment is likely to be nearly the same temperature as the animal itself, so cooling by radiation is not effective. The only plausible way to keep cool is by evaporation, and elephants spray water on their body to accomplish this.

If this is the only possible means of cooling, how many kilograms of water per hour must be evaporated from an elephant's skin to keep it at a constant temperature?

Express your answer using two significant figures.(m/deltaT = ? kg/hour)

Explanation / Answer

Amount of heat needed to be removed from elephants body surface, per hour=2500*3600 J Amount of water which must evaporate from its body surface = 2500*3600/(24*10^5) = 3.75 kg Feel free to revert for any further clarification Cheers PK!

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