A 5000 kgsatellite is orbiting the earth in a Geostationary orbit. The Hight of

Question

A 5000 kgsatellite is orbiting the earth in a Geostationary orbit. The Hight of the satellite above the surface of the earth is? TWo moons orbit a planet in nearly circulr orbits. Moon A has orbital radius r, and moon B has 4r.Moon A takes 20 days What about moon B , how many days B A 5000 kgsatellite is orbiting the earth in a Geostationary orbit. The Hight of the satellite above the surface of the earth is? TWo moons orbit a planet in nearly circulr orbits. Moon A has orbital radius r, and moon B has 4r.Moon A takes 20 days What about moon B , how many days B

Explanation / Answer

T^2 = (4p^2 / GM)r^2 (24*3600)^2 = [(4p^2/(6.67*10^-11)(5.98*10^24) ]r^3 then the heigth
   r = 42.26 *10^6
from the surface = 35.89*10^6 m
(b) From kepler's laws    T^2 a R^3    T1^2 / R1^3 = T2^2 / R2^2
Therefore T2       T2^2 =( R2/R1)^3 (T1)^2
       = (4r/r)^3 (20)^2
   T2 = 160 days
  

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