4. The figure shows a hydraulic lift operated by pumping fluid into the hydrauli

Question

4. The figure shows a hydraulic lift operated by pumping fluid into the hydraulic system. The large cylinder is 40.0 cm in diameter, while the small tube leaving the pump is 1.7 cm in diameter. A total load of 2800 kg is raised 2.30 m at a constant rate. a) What volume of fluid passes through the pump? b) What is the pressure at the pump outlet? c) How much work does the pump do? d) If the lifting takes 40 s, what is the pump power? Neglect pressure variations with height and neglect also the weight of the fluid raised.

Explanation / Answer

V=2.3*40e-2^2*pi/4=0.29(m3). ------------ it is P*40e-2^2*pi/4=2800*9.8 so P=2.18e5(Pa). ------------ It is 2800*9.8*2.3=6.3e4(J) -------------- A=6.3e4/40=1580(W) ---------

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