Figure 5-33 shows an arrangement in which four disks are suspended by cords. The
ID: 1699046 • Letter: F
Question
Figure 5-33 shows an arrangement in which four disks are suspended by cords. The longer, top cord loops over a frictionless pulley and pulls with a force of magnitude 87.5 N on the wall to which it is attached. The tensions in the shorter cords are T1 = 61.3 N, T2 = 40.2 N, and T3 = 8.6 N. What are the masses of (a) disk A, (b) disk B, (c) disk C, and (d) disk D?
Figure 5-33 shows an arrangement in which four disks are suspended by cords. The longer, top cord loops over a frictionless pulley and pulls with a force of magnitude 87.5 N on the wall to which it is attached. The tensions in the shorter cords are T1 = 61.3 N, T2 = 40.2 N, and T3 = 8.6 N. What are the masses of (a) disk A, (b) disk B, (c) disk C, and (d) disk D?Explanation / Answer
The tension acting on the string isnothing but the Weight of the load attached to it. In that manner,T3 is the weight of disk D, T2 is the weight of disks D+C, T1 is the weight of disks D+C+B, and tension of top longer cord is weight of disks D+C+B+A. T3 = md g = 8.6 N. since, acceleration due togravity is 9.8m/sec2, we have mass of disk D = 0.877 kg. T2 = M g = 40.2 N. where M is the mass of disks D and C, which is equal to 4.102kg. therefore, mass of disk C = 4.102 - 0.877 = 3.225 kg. similarly, mass of disks D, C and B is 61.3 /9.8 = 6.255 kg . therefore,mass of disk B = 6.225 - 4.102 = 2.123 kg and mass of all disks is 87.5 /9.8 = 8.928 kg . therefore, mass of disk A = 8.928-6.225 = 2.703 kg. ANSWER: a] mass of disk A = 2.703 kg b]mass of disk B = 2.123 kg c] mass of disk C = 3.225 kg d] mass of disk D = 0.877 kg
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