- For this problem I need to find the tension in the string ( the blue line ). -

Question

 - For this problem I need to find the tension in the string (the blue line).
- The "X" marked by point B in the diagram is the center of mass of the rod.

- THIS IS IMPORTANT (At point "A" is where we mounted the two rods to a vice clamp and suspended them out in the air. More simply put, the horizontal black rod is laying parallel to the floor, but at table top height)

Key Measurements:                 Other Quantities:
AE = 1.025m                   1= 28.5°
ZE = 1.22m                     2= 61.5°
AC = 46.5cm                 Mass of hanging weight = .500kg
AF = 85.5cm                 Mass of horizontal rod = 0.9683kg
FC = 97.3cm                 The tension should be about 17.75N
CD = 27.0cm
CE = 56.0cm
DE = 29.0cm
ZB = 61.0cm

Explanation / Answer

AZ=0.195. AB=0.415. AD=0.735. Net torque about A> T*sin(theta2)*AC=0.9683*9.8*AB+0.5*9.8*AD. so T=18.45

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