T= .841s A= .281 m Find the total energy of the bullet+block+spring system befor

Question

T= .841s

A= .281 m

Find the total energy of the bullet+block+spring system before the bullet enters the block.

Find the total energy of the bullet+block+spring system after the bullet enters the block.

A 6.75 N/m. T= .841s A= .281 m Find the total energy of the bullet+block+spring system before the bullet enters the block. Find the total energy of the bullet+block+spring system after the bullet enters the block. k = 88.0 kg wooden block at rest on a frictionless surface. The block is attached to a spring with m/s embeds itself in a1.57 g bullet traveling at 490

Explanation / Answer

momentum before collision=momentum after collision:0.00675*490=(1.57+0.00675)V V=2.098 m/s conservation of mechanical energy: KE start=PE in spring at end 1/2*1.57675*2.098^2=1/2*88*x^2 x=0.194 m or 194 mm

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.