A 4.00-kg box sits atop a 10.0-kg box on a horizontal table. The coefficient of

Question

A 4.00-kg box sits atop a 10.0-kg box on a horizontal table. The coefficient of kinetic friction between the two boxes and between the lower box and the table is 0.600, while the coefficient of static friction between these same surfaces is 0.800. A horizontal pull to the right is exerted on the lower box, as shown in Fig. 5.15, and the boxes move together. The friction force on the upper box is closest to ?

The answer is 19.3 N to the right
but i don't know how to get it! help please!

A 4.00 - kg box sits atop a 10.0 - kg box on a horizontal table. The coefficient of kinetic friction between the two boxes and between the lower box and the table is 0.600, while the coefficient of static friction between these same surfaces is 0.800. A horizontal pull to the right is exerted on the lower box, as shown in Fig. 5.15, and the boxes move together. The friction force on the upper box is closest to ? The answer is 19.3 N to the right but i don't know how to get it! help please!

Explanation / Answer

where is the figure??? since you have not provided the figure ,am giving the procedure acceleration of the system a= (F-.6*(4+10)*g)/(14) since the boxes are moving together friction force on the upper box = static friction force = 4*a

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