A particle passes through a mass spectrometer as illustrated in the figure below

Question

A particle passes through a mass spectrometer as illustrated in the figure below. The electric field between the plates of the velocity selector has a magnitude of 8074 V/m, and the magnetic fields in both the velocity selector and the deflection chamber have magnitudes of 0.0921 T. In the deflection chamber the particle strikes a photographic plate 55.5 cm removed from its exit point after traveling in a semicircle.

What is the mass-to-charge ratio of the particle?
What is the mass of the particle if it is doubly ionized?
What is its identity, assuming it's an element?

this the problem and the questions corresponding to it. if anyone can help i would be greatly appreciated.

Explanation / Answer

Given that E = 8074 V/m B = 0.0921 T r = 0.555 m What is the mass-to-charge ratio of the particle? m / q = ( r * B) / v = r*B^2 / E = (0.555) *( 0.0921)^2 / 8074 = 5.830 x 10^-7 kg / C What is the mass of the particle if it is doubly ionized? m = q * 5.830 x 10^-7 = 2 e * (5.830 x 10^-7) = 2 * 1.6 x 10^-19 * 5.830 x 10^-7 = 1.865 x 10^-25 kg

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.