In the figure, Indiana Jones is swinging from a rope. The distance between the p
ID: 1696319 • Letter: I
Question
In the figure, Indiana Jones is swinging from a rope. The distance between the pivot point and his center of mass is 31.0 m. He begins swinging from rest at an angle = 17.0o as shown in the figure.
Assuming that Indiana and the rope can be treated as a simple pendulum, what is the value of after 1.26 s (in degrees)?
In the figure, Indiana Jones is swinging from a rope. The distance between the pivot point and his center of mass is 31.0 m. He begins swinging from rest at an angle theta = 17.0o as shown in the figure. Assuming that Indiana and the rope can be treated as a simple pendulum, what is the value of ? after 1.26 s (in degrees)?Explanation / Answer
The length of the pendulum is l = 31 m The initial angle is 17 with the normal Considering the set up as simple pendulum, the man moves a total angle of 4*17 = 68 degree for to complete one complete oscillation. The time taken for to complete one oscillation is T = 2(pi)sqrt(l/g) T = 2(pi)sqrt(31/9.8) T = 11.169 s So the man moves 68 degrees in 11.169 s The angular displacement in 1.26 s is theta = 68*1.26/11.169 theta = 7.67 degrees from his starting position or 9.33 degree with the normal
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